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16x^2-106x-105=0
a = 16; b = -106; c = -105;
Δ = b2-4ac
Δ = -1062-4·16·(-105)
Δ = 17956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17956}=134$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-106)-134}{2*16}=\frac{-28}{32} =-7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-106)+134}{2*16}=\frac{240}{32} =7+1/2 $
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